Question
Download Solution PDFयदि 8 tan A = 5 है, तो \(\frac{8 \sin A-7 \cos A}{8 \sin A+11 \cos A} \) का मान कितना होगा?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
8 tan A = 5
प्रयुक्त सूत्र:
\(\tan A = \dfrac{\sin A}{\cos A}\)
गणना:
दिया गया है:
⇒ \(\dfrac{\sin A}{\cos A} = \dfrac{5}{8}\)
मान लीजिए \(\sin A = 5k\) और \(\cos A = 8k\)
अब, दिए गए व्यंजक में प्रतिस्थापित करते हैं:
⇒ \(\dfrac{8(5k) - 7(8k)}{8(5k) + 11(8k)}\)
⇒ \(\dfrac{40k - 56k}{40k + 88k}\)
⇒ \(\dfrac{-16k}{128k}\)
⇒ \(-\dfrac{1}{8}\)
∴ सही उत्तर \(\frac{-1}{8}\) है।
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