\(\rm \frac{\sec54^{\circ}}{cosec 36^{\circ}}+\frac{\tan70^{\circ}}{\cot20^{\circ}}-2\tan45^{\circ}\) चे मूल्य कशासमान आहे:

Question

Question

This question was previously asked in

SSC CHSL Exam 2023 Tier-I Official Paper (Held On: 08 Aug, 2023 Shift 4)

Answer 1

वापरलेले सूत्र:

Sec (90° - θ) = cosec θ

tan (90° - θ) = cot θ

tan 45° = 1

गणना:

\(\rm \frac{\sec54^{\circ}}{cosec 36^{\circ}}+\frac{\tan70^{\circ}}{\cot20^{\circ}}-2\tan45^ {\circ}\)

⇒ \(\rm \frac{\sec(90^\circ - 36^\circ )}{cosec 36^{\circ}}+\frac{\tan(90^\circ - 20^\circ )}{ \cot20^{\circ}}\) - 2 × tan 45°

⇒ \(\rm \frac{cosec36^\circ }{cosec 36^{\circ}}+\frac{\cot20^\circ}{\cot20^{\circ}}\) - 2

⇒ 1 + 1 - 2 = 0

∴ 0 हे योग्य उत्तर आहे.

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