Question
Download Solution PDFयदि (J + K), 25 है और (J × K), 150 है, तब (J - K) का मान ज्ञात कीजिये|
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया है,
(J + K) = 25 ----(1)
और J × K = 150
उपरोक्त समीकरण का वर्ग करने पर हमें प्राप्त होता है
⇒ (J + K)2 = 252
⇒ J2 + K2 + 2JK = 625
⇒ J2 + K2 = 625 - 300
⇒ J2 + K2 = 325 ----(2)
(J - K) प्राप्त करने के लिए, हमें समीकरण (2) से 2JK घटाना है
⇒ J2 + K2 - 2JK = 325 - 2JK
⇒ (J - K)2 = 325 - 300 = 25
∴ (J - K) = ±5
Last updated on Jul 18, 2025
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