Question
Download Solution PDFశంఖువు యొక్క ఎత్తు 12 సెం.మీ మరియు దాని ఆధార వ్యాసార్థం 14 సెం.మీ. శంఖువు ఘనపరిమాణం ఎంత?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFఇచ్చిన:
శంఖువు ఎత్తు = 12 సెం.మీ
శంఖువు యొక్క వ్యాసార్థం = 14 సెం.మీ
ఉపయోగించిన సూత్రం:
శంఖువు ఘనపరిమాణం = (1/3)πr2h
ఇక్కడ π = 22/7
r = శంఖువు యొక్క వ్యాసార్థం
h = శంఖువు యొక్క ఎత్తు
లెక్కింపు:
శంఖువువాల్యూమ్ = (1/3)πr 2h
⇒ (1/3) × (22/7) × (14)2 × 12
⇒ (22/7) × 14 × 14 × 4
⇒ 22 × 2 × 14 × 4
శంఖువు ఘనపరిమాణం = 2464 సెం.మీ3
Last updated on Jul 14, 2025
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