A మరియు B మాత్రమే ఒక పనిని వరుసగా 4 మరియు 9 రోజులలో చేయగలరు. B తో ప్రారంభించి వారిద్దరూ ప్రత్యామ్నాయ రోజులలో పని చేస్తే ఎన్ని రోజుల్లో పని పూర్తవుతుంది?

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SSC CGL 2023 Tier-I Official Paper (Held On: 18 Jul 2023 Shift 2)
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  1. \(5\frac{1}{3}\)
  2. \(5\frac{2}{3}\)
  3. 5
  4. \(5\frac{1}{4}\)

Answer (Detailed Solution Below)

Option 2 : \(5\frac{2}{3}\)
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Detailed Solution

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ఇవ్వబడింది:

A ఒక పనిని చేయగలడు = 4 రోజులు

B ఒక పనిని చేయగలడు = 9 రోజులు 

ఉపయోగించిన సూత్రం:

మొత్తం పని = సమర్థత × సమయం

లెక్కింపు:

సమర్థత  వ్యక్తి  సమయం  మొత్తం పని
9 A 4 36
4 B 9

ఇప్పుడు,

(B + A) = 4 + 9 = 13 యూనిట్లు = 2 రోజులు

⇒ (13 × 2) = 26 యూనిట్లు = (2 × 2) = 4 రోజులు

⇒ 30 యూనిట్లు = 5 రోజులు

⇒ 36 యూనిట్లు = 5 + (6/9) = 5\(2\over3\) రోజులు

∴ సరైన సమాధానం 5\(2\over3\) రోజులు.

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