Question
Download Solution PDFचौरसाचा कर्ण 8√2 सेमी आहे. दुसऱ्या वर्गाचा कर्ण शोधा ज्याचे क्षेत्रफळ पहिल्या चौरसाच्या क्षेत्रफळाच्या तिप्पट आहे.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept Used:
चौरसाचा कर्ण = √2 a
Calculations:
चौरसाचा कर्ण = √2 a
म्हणून, √2 a = 8√2
⇒ a = 8
⇒ a² = 64 सेमी²
म्हणून, दुसऱ्या चौरसाचे क्षेत्रफळ= 3(64) = 192
म्हणून, त्याचे कर्ण= √2 a = √2 × √192 = 8√6 सेमी
म्हणून, आवश्यक मूल्य 8√6 सेमी आहे
Last updated on Jul 14, 2025
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