If sec θ - cos θ = 14 and 14 sec θ = x, then the value of x is _________.

This question was previously asked in
SSC CHSL 2021 (Held On : 25 May 2022 Shift 2)
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  1. tan2 θ
  2. sec2 θ
  3. 2sec θ
  4. 2tan θ

Answer (Detailed Solution Below)

Option 1 : tan2 θ
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Detailed Solution

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Given:

secθ - cosθ = 14 and 14 secθ = x

Concept used:

\(Sec\theta =\frac{1}{Cos\theta}\)

Calculations:

According to the question,

⇒ \(sec\theta - cos\theta= 14\)

 \(\sec\theta-\frac{1}{sec\theta}=14\)

 \( sec²\theta-1=14sec\theta\)

 \(\tan^2\theta=14sec\theta\)      ----(\(sec²\theta-1=tan^2\theta\))

\(\ tan²\theta=x\)

∴ The value of x is \(tan²\theta\).

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