दी गई आकृति में, Δ PQR में एक वृत्त इस प्रकार बनाया गया है कि यह भुजाओं PQ, QR और RP को क्रमशः बिंदु D, E, F पर स्पर्श करता है। यदि भुजाओं की लम्बाई PQ = 15 सेमी, QR = 11 सेमी और RP = 13 सेमी है, तो PD की लम्बाई ज्ञात कीजिए।

F2 Madhuri SSC 13.02.2023 D3

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  1. 9 सेमी
  2. 8 सेमी
  3. 7.5 सेमी
  4. 8.5 सेमी

Answer (Detailed Solution Below)

Option 4 : 8.5 सेमी
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दिया गया है:

Δ PQR में,

PQ = 15 सेमी, QR = 11 सेमी और RP = 13 सेमी

Δ PQR में एक वृत्त इस प्रकार बनाया गया है कि यह भुजाओं PQ, QR और RP को क्रमशः बिंदु D, E, F पर स्पर्श करता है। 

प्रयुक्त सूत्र:

एक बिंदु से वृत्त पर खींची गई स्पर्श रेखाएँ लम्बाई में बराबर होती हैं।

गणना:

Δ PQR में एक वृत्त इस प्रकार बनाया गया है कि यह भुजाओं PQ, QR और RP को क्रमशः बिंदु D, E, F पर स्पर्श करता है। 

⇒ PD = PF = x                 

⇒ QD = QE = y

⇒ RE = RF = z

सभी स्पर्शरेखाएँ हैं।

⇒ PD + PF + QD + QE + RE + RF = PQ + QR + RP

⇒ x + x + y + y + z + z = 39

⇒ 2x + 2(y + z) = 39

यहाँ,

y + z = QE + ER = RQ

और हमारे पास, RQ = 11 है,

⇒ 2x + 2(11) = 39

⇒ 2x + 22 = 39

⇒ 2x = 17

⇒ x = 8.5

⇒ PD = 8.5 सेमी

सही उत्तर विकल्प 4 है।

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