For the cumulative distribution function \(F(x) = \left\{ {\begin{array}{*{20}{c}} {0;x < - 1}\\ {\frac{1}{2}{{(x + 1)}^2}; - 1 \le x < 0}\\ {1 - \frac{{{{(1 - x)}^2}}}{2};0 \le x < 1}\\ {1.1 < x < \infty } \end{array}} \right.\)

the upper quartile point is

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SSC CGL Tier-II ( JSO ) 2021 Official Paper ( Held On: 10 August 2022 )
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  1. 1 - \(\sqrt{0.25}\)
  2. 1 + \(\sqrt{0.25} \)
  3. 1 + \(\sqrt{0.5}\)
  4. 1 - \(\sqrt{0.5}\)

Answer (Detailed Solution Below)

Option 4 : 1 - \(\sqrt{0.5}\)
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The correct answer is 1-\(\sqrt{0.5}\)

Key Points

  • The cumulative distribution function (CDF) is a function that describes the probability distribution of a random variable.
    • In this case, the CDF is defined by the function F(x), which has different values for different ranges of x.
  • The upper quartile point of a data set is the value that corresponds to the 75th percentile.
  • To calculate the upper quartile point using the CDF, we need to find the value of x for which F(x) is equal to 0.75.
    • To understand this, we can look at the formula for F(x) for the range \(0 ≤ x < 1\).
    • We can see that this part of the function is a quadratic function with a maximum value of 1 at x = 0.
    • In this case, we can see that F(x) is equal to 0.75 when x is equal to\( 1 - √(1/2)\).

Additional Information

  • The upper quartile corresponds to the value of x at which F(x) is equal to 0.75, or the point where 75% of the data is below this value.
  • Since the maximum value of the quadratic function is at x = 0, we can calculate the upper quartile by finding the root of the quadratic equation\( 1 - (1-x)^2/2 = 0.75\), which simplifies to\( (1-x)^2 = 0.5\).
  • Solving for x, we get x = 1 - √(1/2), which is the upper quartile point.
  • Overall, the CDF can be a useful tool for analyzing and modeling probability distributions, and the upper quartile point is a useful measure of variability that can provide insight into the spread and shape of a data set.
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