AB is the diameter of a circle with centre O. If P be point on the circle such that ∠AOP = 110°, then the measure of ∠OBP is:

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SSC CGL 2022 Tier-I Official Paper (Held On : 08 Dec 2022 Shift 1)
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  1. 50° 
  2. 65 °
  3. 60 °
  4. 55 °

Answer (Detailed Solution Below)

Option 4 : 55 °
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Detailed Solution

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Given:

AB is the diameter of a circle with centre O. If P be point on the circle such that ∠AOP = 110°

Formula used:

Sum of the angles of triangle = 180°

Calculations:
F1 Vinanti SSC 21.04.23 D4
As from figure,

⇒ OA = OP = OB = radius

In ΔOPB

⇒ OP = OB

so, ΔOPB is an isosceles triangle

⇒ ∠OPB = ∠OBP = x

As, AB is an striaght line

⇒ ∠AOP + ∠POB = 180°

⇒ ∠POB = 180° - 110° = 70°

In ΔOPB,

⇒ ∠O + ∠P + ∠B = 180°

⇒ 70° + x + x = 180°

⇒ 2x = 180° - 70° = 110°

⇒ x = 55°

⇒ Hence, The measure of the ∠OBP is 55º

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