Question
Download Solution PDFA Reversed Carnot Engine removes 50 kW from a heat sink. The temperature of the heat sink is 250 K and the temperature of the heat reservoir is 300 K. The power required of the engine is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Clausius inequality for a reversible cycle
\(\oint\frac{{dQ}}{T} = 0\)
Calculation:
From Clausius inequality
\(\frac{{50}}{{250}} = \frac{{{Q_H}}}{{300}}\)
QH = 60 kW
Therefore Power = QH - QL = 60 - 50 = 10 kWLast updated on Jul 2, 2025
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