Question
Download Solution PDFएक प्रतिवर्ती कार्नोट इंजन एक ऊष्मा सिंक से 50 kW निकालता है। ऊष्मा सिंक का तापमान 250 K है और ऊष्मा जलाशय का तापमान 300 K है। इंजन की आवश्यक शक्ति क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFअवधारणा:
प्रतिवर्ती चक्र के लिए क्लॉसियस असमानता
\(\oint\frac{{dQ}}{T} = 0\)
गणना:
क्लॉसियस असमानता से
\(\frac{{50}}{{250}} = \frac{{{Q_H}}}{{300}}\)
QH = 60 kW
इसलिए शक्ति = QH - QL = 60 - 50 = 10 kWLast updated on Jul 2, 2025
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