Question
Download Solution PDFThe De-broglie wavelength associated with an electron, accelerated through a potential difference V is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
- The wavelength of the electron due to its motion is called the de-Broglie wavelength of the electron.
- The bundle of light rays is called a photon.
- The de-Broglie wavelength of an electron (λe) is given by:
\(\Rightarrow {λ _e} = \frac{h}{mv}= \frac{12.27}{\sqrt{V}}A^{\circ}\)
- Energy of a photon (E) = (hc)/λ
∴ The wavelength of the photon is
\(⇒ λ =\frac{{h\;c}}{E}\)
Where E = energy, h = Planck constant, m = mass of electron and c = speed of light
Explanation:
- The wavelength associated with an electron accelerated through a potential difference of V is
- The de-Broglie wavelength of an electron (λe) is given by:
\(\Rightarrow {λ _e} = \frac{h}{mv}= \frac{12.27}{\sqrt{V}}A^{\circ}\)
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