Question
Download Solution PDFABCD என்பது இரு சமபக்க சரிவகம் ஆகும், அதாவது AD||BC, AB = 5 செ.மீ, AD = 8 செ.மீ மற்றும் BC = 14 செ.மீ. சரிவகத்தின் பரப்பளவு (செ.மீ2 இல்) என்ன?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFமுக்கோணம் AOB இல் பித்தகோரஸ் தேற்றத்தைப் பயன்படுத்தி மேலே உள்ள படத்தில் இருந்து
⇒ AB2 = BO2 + OA2
⇒ 52 = 32 + OA2
⇒ OA = 4 செ.மீ இது சரிவகத்தின் உயரத்திற்குச் சமம்
⇒ பரப்பளவு = 1/2 × (உயரம்) × (இணையான பக்கங்களின் கூட்டுத்தொகை)
⇒ பரப்பளவு = 1/2 × 4 × (8 + 14) = 44
∴ பரப்பளவு 44 செ.மீ2 ஆகும்.
Last updated on Jul 19, 2025
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