जर 2^x = 4^y = 8^z व \(\frac{1}{2x}+\frac{1}{4y}+\frac{1}{4z}=4\), तर x ची किंमत किती?

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HTET TGT Social Studies 2020 Official Paper

Answer 1

दिलेले आहे:

2x = 4y = 8^z

\(\frac{1}{2x}+\frac{1}{4y}+\frac{1}{4z}=4\)

गणना:

2x = 4y = 8^z

⇒ 2x = 2²y = 2^3z

⇒ x = 2y = 3z

\(\frac{1}{2x}+\frac{1}{4y}+\frac{1}{4z}=4\)

⇒ \(\frac{1}{2x}+\frac{1}{2x}+\frac{3}{4x}=4 \)

⇒ 7/4x = 4

∴ x = 7/16

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