Question
Download Solution PDF200 ग्रॅम लोखंडाचा एक ठोकळा 30°C ते 60°C पर्यंत तापवल्यास त्या ठोकळ्याद्वारे एकूण उष्णता हस्तांतरण किती झाले ? (लोखंडाचा विशिष्ट उष्मा = 450 Jkg-1K-1):
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
पदार्थाची विशिष्ट उष्मा किंवा विशिष्ट उष्मा धारकता:
- पदार्थाच्या एकक वस्तुमानाचे तापमान 1°C (किंवा K) इतके वाढविण्यासाठी आवश्यक असलेल्या उष्णता उर्जेला त्या पदार्थाची विशिष्ट उष्मा म्हणतात.
- हे सामान्यतः C या चिन्हाद्वारे दर्शविले जाते.
⇒ Q = mC∆T
येथे, Q = आवश्यक उष्मा, ∆T = तापमानातील फरक आणि m = पदार्थाचे वस्तुमान.
गणना:
दिलेले आहे:
लोखंडी ठोकळ्याचे वस्तुमान, m = 200 ग्रॅम, लोखंडाची विशिष्ट उष्मा धारकता, C = 450 Jkg-1K-1
तापमानातील फरक = 60 - 30 = 30°C
Q = mCΔT
उष्णतांतरण,
Q = 0.2 x 450 x 30
Q = 2700 J
अशाप्रकारे, पर्याय (3) योग्य आहे.
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