Question
Download Solution PDFएक अप्रवाही उत्क्रमणीय प्रक्रिया के अनुसार होती है, जहाँ P बार में है। यदि दाब 1 बार से 10 बार बदलता है, तो किया गया कार्य क्या होगा? [दिया गया है, ]
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
प्रक्रिया समतापीय है: \( PV = \text{constant} = 15 \)
समतापीय प्रक्रिया में किया गया कार्य:
\( W = \int_{P_1}^{P_2} \frac{15}{P} dP = 15 \cdot \ln\left(\frac{P_2}{P_1}\right) \)
गणना:
\( W = 15 \cdot \ln\left(\frac{10}{1}\right) = 15 \cdot 2.3025 = 34.5375 \, \text{bar·m}^3 \)
\( = 34.5375 \times 10^5 = 3.45375 \times 10^6 \, \text{N·m} = 3.453 \, \text{MN·m} \)
चूँकि दाब बढ़ता है (आयतन घटता है), यह संपीडन है।
Last updated on Jul 15, 2025
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