Question
Download Solution PDFThe humidity ratio of atmospheric air at 28°C [] dry bulb temperature and 760 mm Hg pressure is 0.018 kg/kg of dry air. What will be the relative humidity of air?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Relative humidity is given by:
\( \phi = \frac{P_v}{P_{sat}} \times 100 \)
Where partial vapor pressure is calculated using:
\( P_v = \frac{\omega \times P}{0.622~ + ~\omega} \)
Given:
- \( \omega = 0.018 \)
- \( P = 760 \, \text{mm Hg} \)
- \( P_{sat} = 28.34 \, \text{mm Hg} \)
Calculation:
\( P_v = \frac{0.018 \times 760}{0.622 + 0.018} \approx 21.375 \, \text{mm Hg} \)
\( \phi = \frac{21.375}{28.34} \times 100 \approx {75.42\%} \)
Last updated on Jul 15, 2025
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