Question
Download Solution PDFএকটি রম্বসের প্রতিটি বাহুর দৈর্ঘ্য 13 সেমি এবং একটি কর্ণের দৈর্ঘ্য 24 সেমি। রম্বসটির ক্ষেত্রফল (বর্গ সেমি) কত?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFপ্রদত্ত:
রম্বসের বাহু (a) = 13 সেমি
একটি কর্ণের দৈর্ঘ্য (p) = 24 সেমি
ব্যবহৃত সূত্র:
a = (p2 + q2 )1/2 ÷ 2
রম্বসের ক্ষেত্রফল = 1/2 × p × q
গণনা:
ধরা যাক, রম্বসের অপর কর্ণটি = q
⇒ (242 + q2)1/2 ÷ 2 = 13
⇒ (576 + q2)1/2 = 26
⇒ 576 + q2 = (26)2
⇒ 676 - 576 = q2
⇒ q = √100 = 10
ক্ষেত্রফল = 1/2 × 24 × 10 = 120 বর্গ সেমি
∴ সঠিক উত্তরটি হল 120 বর্গ সেমি।
Last updated on Jul 19, 2025
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