CSAT MCQ Quiz in मल्याळम - Objective Question with Answer for CSAT - സൗജന്യ PDF ഡൗൺലോഡ് ചെയ്യുക

The Correct answer is Option 4. 

Key Points ⇒ ( x + 1/x )² = 2²

⇒ x² + 1/x² + 2 = 4 

⇒ x2 + 1/x2 = 2 

⇒ When We square of x2 + 1/x2 , we will get again 2 

Hence Correct answer is Option 4. 

सही विकल्प 2 है।Key Pointsसही मिलान होगा-

The Correct answer is Option 1

Key Points

Three prime numbers p, q, and r, each less than 20, are such that p – q = q – r

Here, p – q = q – r

Or, 2q = p + r

So, p, q and r are in arithmetic progression.

There are 8 prime numbers under 20: 2, 3, 5, 7, 11, 13, 17 and 19.

Down below are all such combinations wherein three such primes form an A.P.:

⇒ 1. If q = 5, then p and r can be either 3 or 7. Sum of p + q + r = 3 + 5 + 7 = 15.

⇒ 2. If q = 7, then p and r can be either 3 or 11. Sum of p + q + r = 3 + 7 + 11 = 21.

⇒ 3. If q = 11, then p and r can be either 5 or 17. Sum of p + q + r = 5 + 11 + 17 = 33.

⇒ 4. If q = 11, then p and r can also be either 3 or 19. Sum of p + q + r = 3 + 11 + 19 = 33.

⇒ 5. If q = 13, then p and r can be either 7 or 19. Sum of p + q + r = 7 + 13 + 19 = 39.

Thus, there are 4 distinct possible values of (p + q + r).

Hence the Correct answer is Option 1. 

The Correct answer is Option 3. 

Key Points 

Sum of the cubes of first 4 natural numbers = 1³ + 2³ + 3³ + 4³

 = 1 + 8 + 27 + 64 = 100

First even natural number = 2

Required product = 2 × 100 = 200

Hence Correct answer is Option 3. 

The Correct answer is Option 3. 

Key Points

Let’s look at the differences between consecutive terms:

98−117 =−19

80−98 =−18

64−80 =−16

Notice that the differences themselves go: 

−19,−18,−16. The gaps between these differences are:

From  −19 to −18: an increase of  +1

From −18 to −16: an increase of  +2

Hence, it seems each new difference increases by 1 more than the previous increment (+1, then +2, then +3, and so forth).

So, the next difference should be  −16+3=−13. Therefore, the fifth term is: 64+(−13) =51

Hence Correct answer is Option 3. 

Calculation:

⇒ 6 ⊕ 8 = 10

6 + 8 = 14

14 − 4 = 10

⇒ 7 ⊕ 12 = 15

7 + 12 = 19

19 − 4 = 15

⇒ 9 ⊕ 15 = 20

9 + 15 = 24

24 − 4 = 20

⇒ 10 ⊕ 14 = 20

10 + 14 = 24

24 − 4 = 20

Hence, 

⇒ 12 ⊕ 16 ⊕ 9

12 + 16 + 9 = 37 

37 - 4 = 33 

Hence, the Correct answer is Option 4. 

The Correct answer is Option 2. 

Key PointsStep 1: Convert the dimensions of the floor and the tiles to the same units:

• Floor dimensions: 5 m × 3 m = 500 cm × 300 cm.
• Tile dimensions: 150 cm × 75 cm.

Step 2: Calculate the area of the floor and the tiles:

• Area of the floor: 500 cm × 300 cm = 150,000 cm^2.
• Area of one tile: 150 cm × 75 cm = 11,250 cm².

Step 3: Determine how many tiles fit on the floor:

• Number of tiles that fit in the 500 cm length: 500 cm ÷ 150 cm = 3 (since only whole tiles are allowed).
• Number of tiles that fit in the 300 cm breadth: 300 cm ÷ 75 cm = 4.

Step 4: Calculate the total number of tiles:

1. Total number of tiles = 3 × 4 = 12.

Hence Correct answer is Option 2 — 12.

The Correct answer is Option 1. 

Key PointsTo find the number of students who do not play any of the three sports (cricket, football, and hockey), we can use the principle of inclusion-exclusion.

Step 1: Define the sets

• C = number of students playing cricket = 50
• F = number of students playing football = 37
• H = number of students playing hockey = 22
• |C ∩ F| = number of students playing at least cricket and football = 25
• |C ∩ H| = number of students playing at least cricket and hockey = 15
• |F ∩ H| = number of students playing at least football and hockey = 12
• |C ∩ F ∩ H| = number of students playing all three sports = 10

Step 2: Use the inclusion-exclusion principle

⇒ The formula for the number of students playing at least one of the sports is: |C ∪ F ∪ H| = |C| + |F| + |H| - |C ∩ F| - |C ∩ H| - |F ∩ H| + |C ∩ F ∩ H|

Step 3: Substitute the values

⇒  Substituting the values into the formula: |C ∪ F ∪ H| = 50 + 37 + 22 - 25 - 15 - 12 + 10

Calculating step by step:

• Sum of individual sports: 50 + 37 + 22 = 109
• Sum of pairwise intersections: 25 + 15 + 12 = 52
• Now substitute: |C ∪ F ∪ H| = 109 - 52 + 10 = 67

Step 4: Calculate the number of students not playing any sports

The total number of students is 100. Therefore, the number of students who do not play any of the three sports is: Students not playing any sport = 100 - |C ∪ F ∪ H| = 100 - 67 = 33

Thus, the number of students who do not play any of the three sports is: 1) 33

The Correct answer is Option 1. 

Key PointsLet the speed of A be v v and the speed of B be 5/7 v 7/5 ​ v (since B travels at 5/7 ​ of A's speed).

Let the time taken by A to reach the destination be t t hours. Therefore, the time taken by B to reach the destination can be expressed as:

⇒ Time taken by B = Distance / Speed of B = d/ 5/ 7 v =  7d /5 v  ​

⇒ Since distance d d can also be expressed in terms of A's speed and time:  d=vt

⇒ Substituting this into the equation for B's time:

⇒Time taken by B= 7vt / 5v ​ = 7t/5 ​

⇒ According to the problem, B reaches the destination 1 hour 20 minutes after A. Converting 1 hour 20 minutes to hours gives:

⇒ 1 hour 20 minutes = 4 / 3 hours 

⇒ Thus, we can set up the equation: 7t/5 = t + 4/3 ​

⇒ Now, let's solve for  t:

⇒ Multiply through by 15 to eliminate the fractions:

⇒ 15 ⋅ 7t/ 5 = 15 t + 15 ⋅ 4/ 3 

⇒ 21t=15t+20

⇒ Rearranging gives: 21 t − 15 t = 20

⇒ 6 t = 20

⇒ t = 20/6 = 10/3 hour = 3 hour 20 min  

Time taken by B= 7t/5 = 70 / 15 = 14 / 3  hours=4 hours 40 minutes Thus, the time taken by B to reach the destination is: 1) 4 hours 40 minutes.

The correct answer is Option 1

Key PointsStatement 1: The average of four numbers 10, 15, 20, and 25 is 17.5.
⇒ To find the average, we use the formula:  Average = Sum of numbers / Number of numbers
⇒  Calculating the sum: 10+15+20+25=70
⇒  Now, calculating the average: Average=70/4=17.5
Conclusion: Statement 1 is correct.

Statement 2: If a, b, and c are three different natural numbers such that  a+b+c=abc then the average of a, b, and c is 3.
⇒  Let's analyze the equation  a+b+c=abc
⇒  If we assume  a,b,c are the smallest natural numbers that satisfy this equation, we can try  a=1,b=2,c=3
⇒  1+2+3=6 and 1×2×3=6
This satisfies the equation.
⇒  Now, calculating the average: 1 + 2 + 3 / 3 = 6/3 = 2
Conclusion: Statement 2 is incorrect because the average is 2, not 3.
Final Conclusion:
Statement 1 is correct.
Statement 2 is incorrect.
Thus, the correct answer is: 1 only