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Students must be well aware of all the important definitions related to trigonometry Height and Distance.
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Students can find the pictorial representation of all the common terminologies and definitions of height and distance mentioned below.
In trigonometry, heights and distances refer to the measurement and calculation of vertical heights and horizontal distances between objects or points. Trigonometric functions such as sine, cosine, and tangent play a crucial role in solving problems related to heights and distances. These functions allow us to relate angles, sides, and distances within right-angled triangles.
Consider a typical scenario where a person standing at a certain point wants to measure the height of an object or determine the distance between two objects. By using trigonometric concepts and formulas, we can calculate these measurements accurately.
For example, let's say we want to find the height of a tree. We can choose a point on the ground and measure the distance from that point to the tree. Next, we can measure the angle of elevation from the ground to the top of the tree. Using trigonometric ratios, such as the tangent function, we can set up and solve an equation to find the height of the tree.
Similarly, trigonometry can be used to determine distances between two objects. For instance, if we know the height of an observation tower and the angle of depression from the top of the tower to a point on the ground, we can use trigonometry to calculate the horizontal distance between the tower and the point.
By applying trigonometric principles, including the Pythagorean theorem, trigonometric ratios, and the concept of similar triangles, we can solve a wide range of heights and distances problems. These concepts are widely used in various fields, including architecture, surveying, navigation, and physics.
Height can be defined as the measurement of an object in the vertical direction and distance can be defined as the measurement of an object from a particular point in the horizontal direction.
Usually, all government competitive examinations ask questions based on Trigonometry under Quantitative Aptitude.
Trigonometric ratios are used to find the heights and distances of different objects. For instance, if a man is looking at the top of a lamppost. Let the following figure represent different points related to height and distance.
In the above figure, we can see that AB is the horizontal level, which is parallel to the ground and passes through the eye of the observer. AC is the line of sight drawn between the eye of the observer and the top of the lamppost. Angle A formed between the line of sight and the horizontal level can be termed as the angle of elevation.
In order to find the angle of elevation, we can use the trigonometry ratios in the right triangle ABC when the distance between the observer and the lamppost and the height of the lamppost is already given.
We can consider the following table when we have to find the angle of elevation using the different height and distances formula
Angles |
0-degree |
30-degree |
45-degree |
60-degree |
90-degree |
Sin C |
0 |
1/2 |
\(\frac{1}{\sqrt{2}}\) |
\(\frac{\sqrt{3}}{2}\) |
1 |
Cos C |
1 |
\(\frac{\sqrt{3}}{2}\) |
\(\frac{1}{\sqrt{2}}\) |
1/2 |
0 |
Tan C |
0 |
\(\frac{1}{\sqrt{3}}\) |
1 |
\(\sqrt{3}\) |
Not defined |
Cot C |
Not defined |
\(\sqrt{3}\) |
1 |
\(\frac{1}{\sqrt{3}}\) |
0 |
Cosec C |
Not defined |
2 |
\(\sqrt{2}\) |
\(\frac{2}{\sqrt{3}}\) |
1 |
Sec C |
1 |
\(\frac{2}{\sqrt{3}}\) |
\(\sqrt{2}\) |
2 |
Not defined |
To understand the trigonometry height and distance formula, let us understand this using example:
(i) Consider the following figure:
We know that for a right-angle triangle, the common trigonometric ratios are written as:
\(\sin \theta =\frac{p}{h}\)
\(\cos \theta =\frac{b}{h}\)
\(\tan \theta =\frac{p}{b}\)
Here, ‘p’ is the perpendicular, ‘h’ is the hypotenuse and ‘b’ is the base of the right-angled triangle.
(ii) Consider the following figure:
In the given figure, if BD: DC = m: n and \(\angle BAD=\alpha ,\ \angle CAD=\beta ,\ \angle ADC=\theta \),
Then, \(\left(m+n\right)\cot \theta =m\cot \alpha -n\cot \beta \)
(iii) Consider the following figure:
In the given figure, if DE is parallel to AB, then, \(\frac{AB}{DE}=\frac{BC}{DC}\)
(iv) Consider the following figure:
In the above figure, we can calculate the value of distance ‘d’ by:
\(d=h\left(\cot \alpha -\cot \beta \right)\)
Learn about Value of Tan 180
Consider a revolving line OP. Suppose that it revolves around in an anticlockwise direction starting from its initial position OX. The angle is defined as the amount of revolution that the revolving line makes with its initial position.
The angle is taken positive if it is traced by the revolving line in the anticlockwise direction and is taken negative if it is covered in the clockwise direction.
One radian is the angle subtended at the centre of a circle by an arc of the circle, the whole length is equal to the radius of the circle.
Candidates can find the trigonometric ratio chart below.
Angle |
0° |
30° |
45° |
60° |
90° |
120° |
135° |
150° |
180° |
sin θ |
0 |
1/2 |
1/√2 |
√3/2 |
1 |
√3/2 |
1/√2 |
1/2 |
0 |
cos θ |
1 |
√3/2 |
1/√2 |
1/2 |
0 |
– 1/2 |
-1/√2 |
-√3/2 |
-1 |
tan θ |
0 |
1/√3 |
1 |
√3 |
∞ |
-√3 |
-1 |
-1/√3 |
0 |
Candidates should remember the below-mentioned rule to find the sign and magnitude of any trigonometry angle quickly.
Note: Remember these as, Add Sugar To Coffee or After School To College.
Candidates need to be well aware of the important relationships related to various items in Height and Distance math to solve the questions successfully.
Candidates can find different tips and tricks below for solving the height and distance questions related to Trigonometry Height and Distance.
Tip # 1: The angle of elevation is always equal to the angle of depression.
Tip # 2:The angle of elevation of the sun at a particular time from a particular region on earth is always the same.
When you’ve finished with Height and Distance math, you can read about Percentages concepts in-depth here!
Trigonometry is widely used in calculating unknown heights and distances without directly measuring them. These calculations are mostly based on the angle of elevation and angle of depression.
If you know your distance from the building and the angle at which you look up to the top (angle of elevation), you can use trigonometric formulas (like tan θ = height/distance) to find the height.
Pilots use the angle of depression to calculate how far they need to descend to reach the runway. Similarly, trigonometry helps in finding the height of clouds or aircraft.
Surveyors use instruments to measure angles and use trigonometry to find the height of mountains, towers, bridges, and other structures.
Navigators use trigonometry to find the distance to a lighthouse or a ship from the shore using the height of the lighthouse and the angle of depression.
Trigonometry is used to calculate the height or position of stars and satellites above Earth, based on the angle from a point of observation.
By measuring the shadow and angle of elevation of the sun, one can calculate the height of poles or towers.
Question 1: From the top of a building a person looks at a parked car and the angle of depression is θ, if the distance between the foot of the building and the parked car is X unit, in this case, the height of the building will be?
Solution: As the angle of depression is equal to the angle of inclination,
So, in this case tanθ = height of building/X
Therefore, height of building = X tanθ
Question 2: If the height of two towers are X unit and Y unit respectively and the length of shadow of the first tower is Z unit, then the length of shadow of the second tower will be?
Solution: From the help of the second memory tip the angle of elevation in both the figures is the same so both the triangles are similar to each other.
So, X / Z = Y / ?
Hence, ? = ZY / X
Question 3: The angle of elevation of the top of a tower from two points from the ground is complementary and the distance between these points from the foot of the tower are X and Y, then the height of the tower is?
Solution: From figure,
tanθ = TF/X—— (i)
and tan(90°- θ) = TF/Y cotθ = TF/Y ————— (ii)
from (i) and (ii), we get tanθ × cotθ = TF/X × TF/Y ⇒ 1 = (TF)2/XY ⇒ TF = √XY
Therefore, the height of tower will be √XY
Also check Profit and Loss concepts here once you are through with Height and Distance concepts!
Height and Distance questions come up often in various prestigious government exams, some of them are as follows.
We hope you found this article regarding height and distance was informative and helpful, and please do not hesitate to contact us for any doubts or queries regarding the same. You can also download the Testbook App, which is absolutely free and start preparing for any government competitive examination by taking the mock tests before the examination to boost your preparation.
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