Question
Download Solution PDFThe ratio of the present ages of two persons A and B is 4 ∶ 3. If 4 years ago, the ratio of their ages was 2 ∶ 1, what is the present age of A and B (in years) respectively?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
The ratio of the present ages of two persons A and B is 4 ∶ 3.
If 4 years ago, the ratio of their ages was 2 ∶ 1
Calculation:
Let's assume the present ages of A and B are 4x and 3x, respectively.
4 years ago, the ages of A and B were 4x - 4 and 3x - 4, respectively.
The ratio of their ages 4 years ago was (4x - 4) : (3x - 4) = 2 : 1.
So, we can write the equation:
2 / 1 = (4x - 4) / (3x - 4)
Expanding and simplifying the equation, we get:
2 = 4x - 4 / 3x - 4
Multiplying both sides by 3x - 4, we get:
2 × (3x - 4) = 4x - 4
Solving for x, we get:
x = 8.
So, the present age of A is 4x = 4 × 8 = 32 years
The present age of B is 3x = 3 × 8 = 24 years.
A : B = 32 : 24 = 8 : 6
Last updated on Jul 21, 2025
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