9 खेळाडूंमधून 5 खेळाडूंचा संघ किती मार्गांनी निवडला जाऊ शकतो जेणेकरून दोन विशिष्ट खेळाडू नेहमी वगळले जातील?

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NDA 01/2022: Maths Previous Year paper (Held On 10 April 2022)
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  1. 14
  2. 21
  3. 35
  4. 42

Answer (Detailed Solution Below)

Option 2 : 21
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Detailed Solution

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दिलेल्याप्रमाणे:

9 सदस्यांमधून 5 सदस्य निवडले पाहिजे

दोन विशिष्ट सदस्यांना नेहमी वगळले पाहिजे

वापरलेले सूत्र:

nCr = n!/(n – r)! r!

गणना:

प्रश्नानुसार,

दोन सदस्यांना नेहमीच वगळण्यात आले आहे म्हणून आपण प्रत्यक्षात निवडत आहोत

7 सदस्य आणि 5 मार्गां​नी निवडलेल्या सदस्यांची संख्या

7C5 = 7!/(7 – 5)! 5!

⇒(7 × 6 × 5!)/(5! × 2!)

⇒ (7 × 6)/2

⇒ 7 × 3

⇒ 21

मार्गांची संख्या 21 आहे.

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