यदि 4x/3 + [3(7x - 5/8)]/5 = 19/60 है, तो x का मान कितना होगा?

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  1. 1/4
  2. 5/8
  3. 1/8
  4. 3/4

Answer (Detailed Solution Below)

Option 3 : 1/8
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दिया गया है:

(4x/3) + [3(7x - 5/8)]/5 = 19/60

प्रयुक्त सूत्र:

कोष्ठक और भिन्नों को सरल करते हैं, फिर रैखिक समीकरण को हल करते हैं।

गणना:

कोष्ठक को हल करते हैं

3(7x − 5/8) = 21x − 15/8

अब समीकरण बन जाता है:

(4x/3) + (21x − 15/8)/5 = 19/60

(4x/3) + (21x/5 − 15/(8×5)) = 19/60

⇒ (4x/3) + (21x/5) − (15/40) = 19/60

⇒ (4x/3) + (21x/5) = 19/60 + 15/40

60 और 40 का LCM = 120

⇒ RHS = (19 × 2 + 15 × 3)/120 = (38 + 45)/120 = 83/120

3 और 5 का LCM = 15

(4x/3 + 21x/5) = (20x + 63x)/15 = 83x/15

अब समीकरण:

83x/15 = 83/120

⇒ x = (83/120) × (15/83) = 15/120 = 1/8

∴ x का मान 1/8 है

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