A ring of mass 4 kg and radius 2 m is rolling on a surface with an angular velocity of 12 rad/s. Find the linear velocity of a point on the ring at the topmost point of the ring.

Question

Question

Answer 1

CONCEPT:

Whenever a block is rolling on a surface then there is no relative motion of the point of contact of the body with respect to the surface. Then this type of motion is called pure rolling motion or rolling motion.

Here V is liner velocity of center of mass of the body, ω is angular velocity of the body and r is radius

For pure rolling: V = ω r

EXPLANATION:

Given that: Angular velocity (ω) = 12 rad/s

Radius (r) = 2 m

As the ring is in pure rolling motion, so V = ω r = 12 × 2 = 24 m/s

Velocity at topmost point (V’) = V + ω r = 24 + 24 = 48 m/s