A non-flow reversible process takes place according to V=m3, where P is in bar. What will be the work done if the pressure changes from 1 bar to 10 bar? [Given, ln(10)=2.3025]

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  1. 3.453 MN-m, expansion
  2. 3.453 N-m, compression
  3. 3.453 MN-m, compression
  4. 3.453 N-m, expansion

Answer (Detailed Solution Below)

Option 3 : 3.453 MN-m, compression
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Detailed Solution

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Concept:

The process is isothermal:

Work done in isothermal process:

Calculation:

Since pressure increases (volume decreases), it's compression.

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