Asymmetric Synthesis MCQ Quiz in मल्याळम - Objective Question with Answer for Asymmetric Synthesis - സൗജന്യ PDF ഡൗൺലോഡ് ചെയ്യുക

Last updated on Apr 13, 2025

നേടുക Asymmetric Synthesis ഉത്തരങ്ങളും വിശദമായ പരിഹാരങ്ങളുമുള്ള മൾട്ടിപ്പിൾ ചോയ്സ് ചോദ്യങ്ങൾ (MCQ ക്വിസ്). ഇവ സൗജന്യമായി ഡൗൺലോഡ് ചെയ്യുക Asymmetric Synthesis MCQ ക്വിസ് പിഡിഎഫ്, ബാങ്കിംഗ്, എസ്എസ്‌സി, റെയിൽവേ, യുപിഎസ്‌സി, സ്റ്റേറ്റ് പിഎസ്‌സി തുടങ്ങിയ നിങ്ങളുടെ വരാനിരിക്കുന്ന പരീക്ഷകൾക്കായി തയ്യാറെടുക്കുക

Latest Asymmetric Synthesis MCQ Objective Questions

Top Asymmetric Synthesis MCQ Objective Questions

Asymmetric Synthesis Question 1:

The following reaction sequences produce the major stereoisomer
F3 Vinanti Teaching 17.05.23 D82

  1. F3 Vinanti Teaching 17.05.23 D83
  2. F3 Vinanti Teaching 17.05.23 D84
  3. F3 Vinanti Teaching 17.05.23 D85
  4. F3 Vinanti Teaching 17.05.23 D86

Answer (Detailed Solution Below)

Option 4 : F3 Vinanti Teaching 17.05.23 D86

Asymmetric Synthesis Question 1 Detailed Solution

Concept:-

Aldol Condensation:

  • In an aldol reaction, the enolate of an aldehyde or a ketone reacts at the α-carbon atom with the carbonyl of another molecule under basic or acidic conditions to obtain a β-hydroxy carbonyl compound.
  • The mechanism of the aldol reaction is shown below:
    F2 Vinanti Teaching 27.04.23 D110

Explanation:-

  • The reaction pathway is shown below:
    F3 Vinanti Teaching 17.05.23 D87
  • The stereoselectivity can be rationalized by a six-membered (Zimmerman–Traxler) transition state 71, in which the aldehyde approaches from
    the less-hindered face. The product imide can be hydrolyzed to give the enantiomerically pure carboxylic acid or derivative, or reduced to give the primary alcohol product. This procedure, therefore, allows the formation of either enantiomer of the desired syn aldol product.

Conclusion:-

  • Hence, the major stereoisomer will be
    F3 Vinanti Teaching 17.05.23 D86

Asymmetric Synthesis Question 2:

Predict the major predict of the reaction
F3 Vinanti Teaching 17.05.23 D69

  1. F3 Vinanti Teaching 17.05.23 D70
  2. F3 Vinanti Teaching 17.05.23 D71
  3. F3 Vinanti Teaching 17.05.23 D72
  4. F3 Vinanti Teaching 17.05.23 D73

Answer (Detailed Solution Below)

Option 1 : F3 Vinanti Teaching 17.05.23 D70

Asymmetric Synthesis Question 2 Detailed Solution

Explanation:-

  • The reaction pathway is shown below:
    F3 Vinanti Teaching 17.05.23 D74
  • In the first step of the reaction, reduction to the alcohol gives the C2-symmetric compound mannitol.
  • In the next step, mannitol is converted to a useful aldehyde by selective protection as a bis-acetal with acetone and using a Lewis acid ZnCl2.
  • In the last step of the reaction, cleavage of the remaining diol with sodium periodate gives two equivalents of a useful protected form of glyceraldehyde.

Conclusion:-

  • Hence, the major product of the reaction is
    F3 Vinanti Teaching 17.05.23 D70

Asymmetric Synthesis Question 3:

Predict the major product of the reaction below
F3 Vinanti Teaching 17.05.23 D96

  1. F3 Vinanti Teaching 17.05.23 D97
  2. F3 Vinanti Teaching 17.05.23 D98
  3. F3 Vinanti Teaching 17.05.23 D99
  4. F3 Vinanti Teaching 17.05.23 D100

Answer (Detailed Solution Below)

Option 2 : F3 Vinanti Teaching 17.05.23 D98

Asymmetric Synthesis Question 3 Detailed Solution

Concept:-

  • Alkylation of lithiated hydrazones forms the basis of an efficient method for the asymmetric alkylation of aldehydes and ketones, using the optically active hydrazines (S)-1-amino-2-(methoxymethyl)pyrrolidine (SAMP).

F3 Vinanti Teaching 17.05.23 D101

  • Deprotonation of the optically active hydrazones, alkylation, and removal of the chiral auxiliary under mild conditions (ozonolysis or acid hydrolysis of the N-methyl salt) gives the alkylated aldehyde or ketone with, generally, greater than 95% optical purity.

Explanation:-

  • This procedure has been exploited in the asymmetric synthesis of several natural products. Thus, (S)-4-methyl-3- heptanone, the principal alarm pheromone of the leaf-cutting ant Atta texana, was prepared from 3-pentanone in very high optical purity as shown in the scheme below:
    F3 Vinanti Teaching 17.05.23 D102

Conclusion:-

  • Hence,  the major product of the reaction is

F3 Vinanti Teaching 17.05.23 D98

Asymmetric Synthesis Question 4:

The major products A and B formed in the following reaction sequence are

qImage644bd81162cbaf992eb0c407

  1. qImage644bd81162cbaf992eb0c468
  2. qImage644bd81162cbaf992eb0c46a
  3. qImage644bd81262cbaf992eb0c46d
  4. qImage644bd81262cbaf992eb0c470

Answer (Detailed Solution Below)

Option 3 : qImage644bd81262cbaf992eb0c46d

Asymmetric Synthesis Question 4 Detailed Solution

qImage644bd81362cbaf992eb0c490

Correct option is (c)

Asymmetric Synthesis Question 5:

The role of BF3 as an industrial plymerization catalyst is to generate

  1. carbanion
  2. carbocation
  3. organic radical
  4. cation radical

Answer (Detailed Solution Below)

Option 2 : carbocation

Asymmetric Synthesis Question 5 Detailed Solution

Concept: 

→ BF3 is a Lewis acid, which means that it can accept a pair of electrons from a molecule with a lone pair of electrons, such as an alkene monomer. In the case of polymerization, BF3 reacts with the double bond of an alkene monomer to form a complex between BF3 and the alkene.

→ This complex is highly reactive and can undergo a series of reactions that eventually lead to the formation of a carbocation intermediate. The carbocation is a positively charged species that is highly reactive and can react with other alkene monomers to form longer polymer chains.

Explanation:

 The role of BF3 as an industrial polymerization catalyst is to activate the double bond of the alkene monomer and generate a carbocation intermediate that initiates the polymerization reaction.

This mechanism allows for the formation of long polymer chains with specific properties, such as molecular weight and branching.

qImage642ad3587dccdfaaa60c8ad3

 \(\rm H_2O + BF_3 → H^+ + HO\overset \Theta{ B}F_3 \)

cation formation ⇒ carbocation

Conclusion: The correct answer is option 2.

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