Operations on Relations MCQ Quiz in বাংলা - Objective Question with Answer for Operations on Relations - বিনামূল্যে ডাউনলোড করুন [PDF]

Last updated on Apr 17, 2025

পাওয়া Operations on Relations उत्तरे आणि तपशीलवार उपायांसह एकाधिक निवड प्रश्न (MCQ क्विझ). এই বিনামূল্যে ডাউনলোড করুন Operations on Relations MCQ কুইজ পিডিএফ এবং আপনার আসন্ন পরীক্ষার জন্য প্রস্তুত করুন যেমন ব্যাঙ্কিং, এসএসসি, রেলওয়ে, ইউপিএসসি, রাজ্য পিএসসি।

Latest Operations on Relations MCQ Objective Questions

Top Operations on Relations MCQ Objective Questions

Operations on Relations Question 1:

Let P(n)=n2 + n is odd, then P(n) = P(n + 1)∀n and P(1) is not true, then which of the following is true?

  1. P(n) is false for all n ∈ N.
  2. P(n) is true for all n.
  3. P(n) is true for all n ∈ Z.
  4. P(n) is true for all n ≥ N.

Answer (Detailed Solution Below)

Option 1 : P(n) is false for all n ∈ N.

Operations on Relations Question 1 Detailed Solution

Given,

P(n) = n2 + n is odd      ---(1)

P(n) = P(n + 1) ∀n

P(1) = not true

P(n) = n(n + 1)

Thus ,P(n) is a product of two consecutive numbers & one of them must be odd & other will be even & the product of one odd & one even number will always results in even number, thus P(n) will always be even 

Thus P(n) is false for all n ∈ N

Operations on Relations Question 2:

Let R be a relation such that R = {(1, 2), (9, 7), (2, 5), (2, 3), (7, 3)} then what will be R-1OR-1 

  1. {(3, 1), (5, 1) (3, 9), (7, 3)}
  2. {(3, 1), (5, 1), (7, 3)}
  3. {(3, 1), (5, 1) (3, 9)}
  4. {(3, 1), (3, 9), (7, 3)}

Answer (Detailed Solution Below)

Option 3 : {(3, 1), (5, 1) (3, 9)}

Operations on Relations Question 2 Detailed Solution

Concept:

If A, B and C are three sets such that  \(R\subseteq A\times B\) and \(S\subseteq B\times C\) then (SOR)-1 = R-1 O S-1. It is clear that if a R b, b S c ⇒ a SOR c.

Calculation:

We know that  (ROR)-1 = R-1OR-1

Domain(R) = {1, 2, 7, 9} and Range(R) = {2, 3, 5, 7}

we see that,

1 → 2 → 3 ⇒ (1, 3) ∈ ROR

1 → 2 → 5 ⇒ (1, 5) ∈ ROR

9 → 7 → 3 ⇒ (9, 3) ∈ ROR

Hence ROR = {(1, 3), (1, 5), (9, 3)}

(ROR)-1 = {(3, 1), (5, 1), (3, 9)}

 R-1OR-1 = {(3, 1), (5, 1), (3, 9)}

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