Question
Download Solution PDFUncertainty in the position of an electron moving with a velocity of 200 m/s, accurate up to 0.01%, will be:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCONCEPT:
Heisenberg's Uncertainty Principle
- Heisenberg's uncertainty principle states that it is impossible to simultaneously determine the exact position and exact momentum (or velocity) of a particle.
- The uncertainty in position (Δx) and momentum (Δp) are related by:
Δx × Δp ≥ h / 4π
where h is Planck's constant (6.626 × 10-34 J·s). - Momentum (p) is given by:
p = m × v
where m is the mass and v is the velocity. - Uncertainty in momentum (Δp) can be calculated as:
Δp = m × Δv
where Δv is the uncertainty in velocity.
EXPLANATION:
- Given:
- Velocity of the electron (v) = 200 m/s
- Accuracy of velocity = 0.01%
- Mass of electron (m) = 9.1 × 10-31 kg
- Planck's constant (h) = 6.626 × 10-34 J·s
- Uncertainty in velocity (Δv):
- Δv = (0.01 / 100) × 200
- Δv = 0.02 m/s
- Uncertainty in momentum (Δp):
- Δp = m × Δv
- Δp = (9.1 × 10-31) × (0.02)
- Δp = 1.82 × 10-32 kg·m/s
- Uncertainty in position (Δx):
- Δx × Δp ≥ h / 4π
- Δx ≥ h / (4π × Δp)
- Δx ≥ (6.626 × 10-34) / (4 × 3.1416 × 1.82 × 10-32)
- Δx ≥ 2.9 × 10-3 m
Therefore, the uncertainty in the position of the electron is approximately 2.9 × 10-3 m.
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