Question
Download Solution PDFThe speed of train P is 180 km/hr and the train can cross a pole in 4 seconds. Train P can cross a man who sitting in train Q in 10 seconds, while both trains running in same direction.
Quantity I: Speed of train Q (in m/sec.).
Quantity II: If speed of train P is decrease by 20 m/sec., then find the new speed of train P (in m/sec.)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCalculation
Speed of train P (in m/sec.) = 180 × 5 18 = 50 m/sec.
Length of train P = 50 × 4 = 200 meters
Relative speed of train P and Q = 200/10 = 20 m/sec.
So, speed of train Q = 50 – 20 = 30 m/sec.
Quantity I: Speed of train Q = 30 m/sec.
Quantity II: New speed of train P = 50 – 20 = 30 m/sec.
So, Quantity I = Quantity II
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