The circuit shown in figure is at steady state with the switch in the open position. What is the current through the inductor immediately after closing the switch?

Explanation:.

Analysis:

Let us analyze the circuit step by step:

• Steady-State Condition: Before the switch is closed, the inductor behaves like a short circuit. The current through the inductor at this point can be calculated based on the voltage source and the resistor network in the circuit.
• Immediate Condition After Closing the Switch: When the switch is closed, the inductor maintains its current continuity property. Thus, the current through the inductor remains the same as it was before the switch was closed.

From the circuit diagram (not provided here but assumed based on the statement), we can use Ohm's Law and the properties of the resistor network to compute the steady-state current through the inductor:

Let the voltage source be V, and the resistors in the circuit be R. Assuming the steady-state current through the inductor is I, we calculate:

I = V / R

Given that the calculated current before the switch is closed is 1 A, this value remains unchanged immediately after the switch is closed because of the inductor's current continuity property.

Correct Option:

The correct answer is Option 3: 1 A. The current through the inductor immediately after closing the switch is 1 A