Question
Download Solution PDFవక్ర ఉపరితల వైశాల్యం దాని భూమి వైశాల్యం రెండింతలు ఉన్న ఘన శంఖువు 6√3 సెం.మీ వాలు ఎత్తును కలిగి ఉంటుంది. దీని ఎత్తుని కనుగొనండి?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFఇచ్చింది:
శంఖువు యొక్క వక్ర ఉపరితల వైశాల్యం = 2 × శంఖువు యొక్క భూమి వైశాల్యం
ఉపయోగించబడిన భావన:
ఉపయోగించబడిన సూత్రం
శంఖువు యొక్క వాలు ఎత్తు (l). = √r2 + h2
శంఖువు యొక్క CSA = πrl
గణన:
శంఖువు యొక్క వ్యాసార్థం r యూనిట్లుగా అనుకుందాం.
⇒ πrl = 2πr2
⇒ l = 2r
⇒ r = 6√3/2
⇒ r = 3√3
శంఖువు యొక్క వాలు ఎత్తు (l) = √r2 + h2
⇒ 6√32 = 3√32 + h2
⇒ h2 = 108 - 27 = 81
⇒ h = 9 సెం.మీ
∴ సమాధానం 9 సెం.మీ.
Last updated on Jul 21, 2025
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