Velocity for a two dimensional flow is given by What will be the velocity at a point (1, 2) after 2 seconds?

Concept:

To determine the velocity at a specific point in a two-dimensional flow field, we need to analyze the given velocity field equation and evaluate it at the specified point and time.

Given:

• Point coordinates: (1, 2)
• Time: 2 seconds

Step 1: Identify the velocity field equation

The problem mentions a velocity field equation, but it is not explicitly provided in the given content. Typically, a two-dimensional velocity field is expressed as:

\(\vec{V} = u(x,y,t)\hat{i} + v(x,y,t)\hat{j}\)

where u and v are the velocity components in the x and y directions, respectively.

Step 2: Evaluate the velocity components at (1, 2) and t = 2s

Without the specific velocity field equation, we cannot compute the exact velocity components. However, the problem provides multiple-choice options, suggesting that the calculation leads to one of these values.

Step 3: Calculate the velocity magnitude

The magnitude of the velocity vector is given by:

\(|\vec{V}| = \sqrt{u^2 + v^2}\)