Question
Download Solution PDFTwo concentric circles are of radii 10 cm and 6 cm. Find the length of the chord of the larger circle which touches the smaller circle.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCalculation
The perpendicular bisector of any chord passes through the centre of the circle,
OP ⊥ AB
In OPB, ∠OPB = 900
PB2 = OB2 – OP2
⇒ PB2 = 102 – 62
⇒ PB2 = 64
⇒ PB2 = 82
⇒ PB = 8 cm
OP bisects AB
⇒ AP = PB = 8 cm
∴ AB = AP + PB = 8 + 8 = 16 cm
The length of AB is 16 cm.
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