Question
Download Solution PDF2, 5, 6, 7 మరియు 8 అంకెలతో ఎన్ని నాలుగు అంకెల సంఖ్యలు ఏర్పడతాయి? (పునరావృతమైన అంకెలు అనుమతించబడవు)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFఇవ్వబడింది:
5 సంఖ్యలకు 2, 5, 6, 7 మరియు 8 ఇవ్వబడ్డాయి
పునరావృతం లేకుండా నాలుగు అంకెల సంఖ్య
ఉపయోగించిన సూత్రం:
పునరావృతం కానపుడు ప్రస్తారం = \(\frac{n!}{(n \ - \ r)!}\)
ఇక్కడ n = మొత్తం సాధ్యమయ్యే సంఖ్యలు
r = అవసరమైన సంఖ్య
గణన:
ఇక్కడ మొత్తం సాధ్యం అయ్యే సంఖ్య n = 5
మరియు అవసరమైన సంఖ్య r = 4
సూత్రాన్ని వర్తింపచేయగా
\(\frac{5!}{(5\ - \ 4)!}\)
⇒ 5!
⇒ 5 × 4 × 3 × 2 × 1 = 120
∴ 120 సాధ్యమయ్యే నాలుగు అంకెల సంఖ్య ఉంటుంది.
Last updated on Jul 18, 2025
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