கீழ்காணும் படத்தில், PA = 15 செ.மீ, PD = 6 செ.மீ, CD = 4 செ.மீ எனில், AB இன் மதிப்பு என்ன?

523

  1. 1.5 செ.மீ
  2. 3 செ.மீ
  3. 4.5 செ.மீ
  4. 11 செ.மீ

Answer (Detailed Solution Below)

Option 4 : 11 செ.மீ
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இந்தப் படத்தில்

PB = x என்க

வர்க்கச் செகண்டின் பண்பின்படி

PB x PA = PD x PC [PC = PD + CD]

x x 15 = 6 x 10

x = 4 = PB

AB = 15 - 4 = 11 செ.மீ
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