Neglecting saturation, if the current taken by DC series motor is increased from 10A to 12A, percentage increase in the torque will be

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  1. 44%
  2. 40%
  3. 20%
  4. 16%

Answer (Detailed Solution Below)

Option 1 : 44%
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Explanation:

DC Series Motor Torque Calculation:

Definition: The torque (T) produced by a DC series motor is directly proportional to the square of the armature current (Ia) under normal operating conditions, where magnetic saturation is neglected. Mathematically, this relationship can be expressed as:

T ∝ Ia2

This means that any change in the armature current will result in a corresponding change in the torque, following a quadratic relationship.

Given Data:

  • Initial current, Ia1 = 10 A
  • Final current, Ia2 = 12 A

Objective: To calculate the percentage increase in torque when the current increases from 10 A to 12 A.

Step-by-Step Solution:

  1. Expression for torque: Since torque is proportional to the square of the armature current, we can write:

T1 ∝ Ia12 and T2 ∝ Ia22

  1. Ratio of torques: To find the percentage increase in torque, calculate the ratio of the final torque (T2) to the initial torque (T1):

T2/T1 = (Ia2/Ia1)2

Substituting the given values of Ia1 and Ia2:

T2/T1 = (12/10)2

T2/T1 = (1.2)2 = 1.44

  1. Percentage increase in torque: The percentage increase in torque is given by:

Percentage Increase = [(T2 - T1)/T1] × 100

Substituting T2/T1 = 1.44:

Percentage Increase = [(1.44 - 1) × 100] = 0.44 × 100 = 44%

Thus, the percentage increase in torque is 44%.

Hence the current Option 1 is (0.44 or 44%)

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