Question
Download Solution PDFएका शंकूचा पाया एक आयत आहे ज्याची लांबी आणि रुंदी अनुक्रमे 16 सेमी आणि 12 सेमी आहे. उजव्या आयताकृती शंकूच्या शिरोबिंदूतून जाणार्या सर्व बाजूकडील कडांची लांबी 26 सेमी असल्यास, शंकूचे घनफळ घन सेंटीमीटरमध्ये शोधा.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFआयताची लांबी l = 16 सेमी
आयताची रुंदी b = 12 सेमी
आयताचा कर्ण = √(l2 + b2) = √(122 + 162) = 20
बाजूकडील कडांची लांबी = 26 सेमी
शंकूची उंची H मानू.
जसे की आपल्याला माहीत आहे,
(बाजूकडील कडांची लांबी)2 = (पिरॅमिडची उंची)2 + [(पायाच्या कर्णाची लांबी)/2]2
262 = H2 + (20/2)2
⇒ H2 = 262 - 102
⇒ H = √576 = 24
जसे की आपल्याला माहीत आहे,
शंकूचे घनफळ = (1/3) × पायाचे क्षेत्रफळ × उंची
शंकूचे घनफळ = (1/3) × 16 × 12 × 24 = 1536 सेमी3
Last updated on Jul 17, 2025
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