Question
Download Solution PDFരണ്ട് വൃത്തങ്ങളുടെ ആരം 20 സെന്റീമീറ്ററും 18 സെന്റീമീറ്ററുമാണ്. രണ്ട് വൃത്തങ്ങളും രണ്ട് പോയിന്റുകളിൽ പരസ്പരം ഛേദിക്കുന്നു. അവയുടെ പൊതുവായ ഞാണിന്റെ നീളം 16 സെ.മീ. ആണ്. അപ്പോൾ, അവയുടെ കേന്ദ്രങ്ങൾ (സെന്റിമീറ്ററിൽ) തമ്മിലുള്ള ദൂരം എന്താണ്?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFനൽകിയിരിക്കുന്നത്, CD = 16 cm
∴ CE = 16/2 = 8 cm
ഇപ്പോൾ, ΔACE- ൽ
AE2 = AC2 - EC2
⇒ AE2 = (20)2 - 82
⇒ AE2 = 400 - 64
⇒ AE2 = 336
⇒ AE = √336
⇒ AE = 4√21 cm
ΔCEB- യിൽ,
EB2 = CB2 - CE2
⇒ EB2 = 182 - 82
⇒ EB2 = 324 - 64
⇒ EB2 = 260 cm
⇒ EB = 2√65 cm
∴ കേന്ദ്രങ്ങൾ തമ്മിലുള്ള ദൂരം (AB) = AE + EB = (4√21 + 2√65) cm
Last updated on Jul 19, 2025
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