Question
Download Solution PDF50 Hz पर 220 V की AC विद्युत आपूर्ति से, 20 Ω का एक प्रतिरोधक, 25 Ω प्रतिघात का एक संधारित्र तथा 45 Ω प्रतिघात का एक प्रेरक श्रेणीक्रम में जुड़े हुए हैं। परिपथ में संगत धारा और धारा तथा वोल्टता के बीच का कला कोण क्रमशः है:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसही विकल्प: (2) 7.8 A और 45° है।
XL = 45 Ω, XC = 25 Ω, R = 20 Ω
⇒ I = 220 / √((XL - XC)² + R²) = 220 / √((45 - 25)² + 20²)
⇒ = 220 / (2√2) = 11 / √2 = 7.779 A
⇒ tan φ = (XL - XC) / R = (45 - 25) / 20 = 1
⇒ φ = 45°
Last updated on Jun 16, 2025
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