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संकल्पना:
किसी द्विघात समीकरण के लिए आइए मानते हैं
ax2 + bx + c = 0
मूलों का योग = -b/a
मूलों का गुणनफल = c/a
हल:
⇒
⇒
⇒
उपरोक्त की ax2 + bx + c = 0 से तुलना करने पर, हम प्राप्त करेंगें,
a = 1, b = (p + q -2r), c = [pq + (p + q) r]
प्रश्न के अनुसार, दिए गए समीकरण के मूल परिमाण में बराबर और चिह्न में विपरीत हैं।
माना
मूलों का योग = [
⇒ -b/a = -(p + q - 2r) = 0
⇒ p + q = 2r
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