A full wave rectifier circuit with diodes (D₁) and (D₂) is shown in the figure. If input supply voltage Vin = 220sin (100πt) volt, then at t = 15 m sec
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  1. D₁ is forward biased, D₂ is reverse biased
  2. D₁ is reverse biased, D₂ is forward biased
  3. D₁ and D₂ both are forward biased
  4. D₁ and D₂ both are reverse biased

Answer (Detailed Solution Below)

Option 2 : D₁ is reverse biased, D₂ is forward biased
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Correct option is: (2) D1 is reverse biased, D2 is forward biased

qImage681c50959ef4a58a2324f7c5

Vin = 220 × sin(100πt) volt

Given: t = 15 ms = 0.015 s

ω = 100π

2π / T = 100π

⇒ T = 1 / 50 s

⇒ T = 0.02 s

Now, t = (3T / 4)

i.e., the signal is in the negative half cycle.

So now the negative half cycle is fed to the circuit, making D1 reverse biased and D2 forward biased.

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