Question
Download Solution PDFA battened column subjected to an axial force of 1100 kN. Battens are placed at 1.25 m centre to centre. Depth of batten plate is 300 mm, length is 363 mm, thickness is 6 mm and on two planes. The bending moment in the batten is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The design shear and moments for batten plates is given by,
\({{\rm{V}}_{\rm{b}}} = \frac{{{{\rm{V}}_{\rm{t}}}{\rm{C}}}}{{{\rm{NS}}}}\) and \({\rm{M}} = \frac{{{{\rm{V}}_{\rm{t}}}{\rm{C}}}}{{2{\rm{N}}}}\)
Where,
Vt = Transverse shear force (2.5% of axial load)
C = Distance between centre to centre of battens longitudinally
N = Number of parallel planes
S = Minimum transverse distance between the centroid of the fasteners connecting batten to the main member.
Calculation:
Given: C = 1.25 m, and N = 2
Vt = 2.5% of axial force = 1100 × 2.5/100 = 27.5 kN
∴ Bending moment, \({\rm{M}} = \frac{{27.5 \times 1.25}}{{2 \times 2}} = 8.6{\rm{\;kNm}}\)Last updated on Jul 9, 2025
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